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9x^2-115x+300=0
a = 9; b = -115; c = +300;
Δ = b2-4ac
Δ = -1152-4·9·300
Δ = 2425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2425}=\sqrt{25*97}=\sqrt{25}*\sqrt{97}=5\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-115)-5\sqrt{97}}{2*9}=\frac{115-5\sqrt{97}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-115)+5\sqrt{97}}{2*9}=\frac{115+5\sqrt{97}}{18} $
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